Solve complex quadratic equations by completing the square .
(vi) 3z2−5z+7=0
Solution
Divide both sides by 3:z2−35z+37=0Isolate the constant term:z2−35z=−37Add (2−5/3)2=(−65)2=3625 to both sides:z2−35z+3625=−37+3625(z−65)2=−3684+3625=−3659Take square root:z−65=±−3659=±6i59z=65±6i59=65±i59