Find roots and express as a product of linear factors:z4+7z2−144=0.
Solution
Let u=z2 to form a quadratic equation:z4+7z2−144=0⟹u2+7u−144=0Quadratic formula: u=2a−b±b2−4acu=2(1)−7±49−4(1)(−144)=2−7±49+576=2−7±625=2−7±25u=2−7+25=218=9oru=2−7−25=2−32=−16Since u=z2, we have z2=9 or z2=−16z2=9⟹z=±3z2=−16⟹z=±4i(since −16=±4i)Therefore, the roots are: 3,−3,4i,−4iUsing the factor theorem:z4+7z2−144=(z−3)(z+3)(z−4i)(z+4i)