Let u=z2:u2+21u−100=0Discriminant:Δ=212−4(1)(−100)=441+400=841Δ=29Solve for u:u=2−21±29u1=2−21+29=28=4,u2=2−21−29=2−50=−25So:z4+21z2−100=(z2−4)(z2+25)Factor each:z2−4=(z−2)(z+2)z2+25=(z−5i)(z+5i)Therefore:z4+21z2−100=(z−2)(z+2)(z−5i)(z+5i)